Matematika

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tolong dibantu yaaaaaaa

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  • dari soal sin A = 1/2 didapat cos A = (akar 3)/2.
    dari cosB = (akar3)/2 didapat sinB = 1/2.
    a) cos (A+ B) = cosA.sinB + sin A.cos B
    = (akar3)/2.1/2 + 1/2.(akar3)/2
    =1/2.(akar3)/2 + 1/2(akar3)/2
    = (akar3)/2
    b) cos (A-B)= cosA.sinB - sinA.cos B
    = (akar3)/2.1/2 - 1/2.(akar3)/2
    =0

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