x^2-(k-3)x-k+6=0 akar real berqpa batas nilai k
Matematika
erfansyahdre
Pertanyaan
x^2-(k-3)x-k+6=0 akar real berqpa batas nilai k
1 Jawaban
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1. Jawaban Taufik01
x^2-(k-3)x-k+6=0
b^2-4ac=0
-(k-3)-4(1)(-k+6)=0
-k+3-4(-k+6)=0
-k+3+4k-24=0
3k-21=0
3k=21
k=21/3
k=7