Keliling alas sebuah kerucut 88 cm. Jika tinggi kerucut = 24 cm dan phi = 22/7 , maka volume kerucut adalah?

K = 22/7 * d = 88
d= 28cm
r= 14 cm
t= 24cm

maka volumenya,
V= 1/3 * 22/7 * 14 * 14 * 24 = 4928 cm3

k.alas = 22/7 × r²
r² = k.alas/22/7
r² = 88 × 7/22
r² = √28
r² = √4 × √7
r² = 2√7

v. kerucut = 1/3 ×l. alas×tinggi
v kerucut  = 1/3×22/7×2√7×2√7×24
v. kerucut = 1/8×22/7×4√14
v. kerucut = 22/56×4√14
v. kerucut = 11/26×4√14
v. kerucut = 11/13×2√14