x/4 - 3 > x/3 + 2 tolong bantu beserta cara pengerjaannya :)

[tex]\frac{x}{4}-3>\frac{x}{3}+2 \\ \frac{x}{4}-\frac{x}{3}>2+3 \\ \frac{3-4}{12}x>5 \\ -\frac{1}{12}x>5 \\ x<-60[/tex]

x/4 - 3 > x/3 + 2
x/4 - x/3 > 2 +3
3x/12 - 4x/12 > 5
-x/12 > 5
-x < 5.12
-x < 60
x < -60