Mohon bantu yang nomor 10 yaa ehe
Matematika
Cherishtaa
Pertanyaan
Mohon bantu yang nomor 10 yaa ehe
1 Jawaban
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1. Jawaban newwiguna
PQ² = PR² - RQ²
PQ² = 25² - 15²
PQ² = 625 - 225
PQ² = 400
PQ = √400
PQ = 20
==================
PS² = PR² - SR²
PS² = 25² - 7²
PS² = 625 - 49
PS² = 576
PS = √576
PS = 24
======================
sin (x + y)° = sin x . cos y + cos x . sin y
= SR/PR . PQ/PR + PS/SR . RQ/PR
= 7/25 . 20/25 + 24/25 . 15/25
= 140/625 + 360/625
= 500/625
= 4/5
jawaban E