Matematika

Pertanyaan

Mohon bantu yang nomor 10 yaa ehe
Mohon bantu yang nomor 10 yaa ehe

1 Jawaban

  • PQ² = PR² - RQ²
    PQ² = 25² - 15²
    PQ² = 625 - 225
    PQ² = 400
    PQ = √400
    PQ = 20

    ==================
    PS² = PR² - SR²
    PS² = 25² - 7²
    PS² = 625 - 49
    PS² = 576
    PS = √576
    PS = 24

    ======================
    sin (x + y)° = sin x . cos y + cos x . sin y
                      = SR/PR . PQ/PR + PS/SR . RQ/PR
                      = 7/25 . 20/25 + 24/25 . 15/25
                      = 140/625 + 360/625
                      = 500/625
                      = 4/5

    jawaban E