Matematika

Pertanyaan

di ketahui ×=26,y=23,dan z=19.tentukanlah :
a.2x - 3y +z
b.x + y - z
c.x² - y² +z
d.(x - y)² + 3z

2 Jawaban

  • a ) 2x - 3y + z
    @ 2(26) - 3(23) + 19
    @ 52 - 69 + 19
    @ 2

    b) x + y - z
    @ 26 + 23 - 19
    @ 30

    c) x^2 - y^2 + z
    @ (26)^2 - (23)^2 + 19
    @ 676 - 529 + 19
    @ 166

    d) (x-y)^2 + 3z
    @ (26-23)^2 + 3(19)
    @ (3)^2 + 57
    @ 9 + 57
    @ 66

    Semoga membantu.. ^_^
  • 1. (2*26) - (3*23) + 19 = 52 - 69 + 19 = 2
    2. 26 + 23 - 19 = 30
    3. 26² - 23² + 19 = 676 - 529 + 19 = 166
    4. (26-23)² + (3*19) = (3)² + 57 = 9 + 57 = 66

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