Tolong jawab menggunakan cara ya, terima kasih :)

massa CH3COOH = 30 %

ρ CH3COOH = 1,04 x 9 cm-3 = 9,36 g/mL

Mr CH3COOH = 60 gr/mol

M = …………………………………..?

Misalkan massa larutan = 100 gr, maka volume CH3COOH yaitu:

Massa CH3COOH = 30% x 100 gr

Massa CH3COOH = 30 gr

jumlah mol CH3COOH = massa/Mr

jumlah mol CH3COOH = 30 gr /(60 gr/mol)

jumlah mol CH3COOH = 0,5 mol

V larutan = massa/ρ

V larutan = 100 gr /(9,36 g/mL)

V larutan = 10,68 mL

V larutan = 0,011 L

M = jumlah mol/V

M = 0,5 mol /0,011 L

M = 45,5 mol/L