tolong jawab yg udah di jawab yaitu no. 23,25,1.a,1.c,2.b, 2.e, 2.f, 3.b,3.e yg lain tolong jawab, jan asal jawab pliss.. yg asal jawab hati hati aja.. ;)

Nomor 15
[tex]\displaystyle \frac{3\sqrt{18}\times 2\sqrt{48}}{4\sqrt{3}}\\ =\frac{9\sqrt{2}\times 8\sqrt{3}}{4\sqrt{3}}=18\sqrt{2}[/tex]

Nomor 16
[tex]\displaystyle \left ( \sqrt{m^{\frac{2}{3}}n^{1\frac{3}{4}}} \right )^4\\ =\left ( m^{\frac{2}{3}}n^{1\frac{3}{4}} \right )^2\\ =m^\frac{4}{3}n^\frac{7}{2}=mn^3~\sqrt[6]{m^2n^3}[/tex]

Nomor 17
[tex]\displaystyle \sqrt[4]{16^{x+5}}=4^{x+3}\\ =\left ( (4^2)^{x+5} \right )^\frac{1}{4}=4^{x+3}\\ =\frac{1}{4}(2x+10)=x+3\\ x=-1[/tex]

Nomor 18
√6 (2√3 - √32)
= √6 (2√3 - 4√2)
= 2√18 - 4√12 = 6√2 - 8√3

Nomor 19
(√6 + √3)(2√3 - √6)
= 6√2 - 6 + 6 - 3√2 = 3√2

Nomor 20
(√5 + √3)²
= 5 + 2√15 + 3 = 8 + 2√15

Nomor 21
(4a√3 - 3)²
= 48a² - 2(4a√3)(3) + 9 = 48a² - 12a√3 + 9

Nomor 23
[tex]\displaystyle \frac{5}{5+\sqrt{3}}\\ =\frac{5}{5+\sqrt{3}}~\frac{5-\sqrt{3}}{5-\sqrt{3}} =\frac{25-5\sqrt{3}}{22}[/tex]

Nomor 24
[tex]\displaystyle \frac{3}{\sqrt{a}-2\sqrt{b}}\\ =\frac{3}{\sqrt{a}-2\sqrt{b}}~\frac{\sqrt{a}+2\sqrt{b}}{\sqrt{a}+2\sqrt{b}}=\frac{3\sqrt{a}+6\sqrt{b}}{a-4b}[/tex]

Nomor 1.b
[tex]\displaystyle \left [ \left (-\frac{3}{2x} \right )^{-3} \right ]^2\\ =\left (-\frac{3}{2x} \right )^{-6}=\frac{\frac{1}{729}}{\frac{1}{64}x^{-6}}=\frac{64x^6}{729}[/tex]

Nomor 3.a
[tex]\displaystyle 16^\frac{1}{2}+8^\frac{2}{3}-81^\frac{1}{4}\\ =4+4-3=5[/tex]

Nomor 3.d
5√12 + 4√75
= 10√3 + 20√3 = 30√3

Nomor 3.f
6√20 + 2√75 - 4√5 + 3√48
= 12√5 + 10√3 - 4√5 + 12√3 = 22√3 + 8√5