diketahui fungsi f(x)=3-2x^2 g(x)=12 tentukan 1. (f+g) (7) 2. (fxg) (24) 3. (fog) (14)

Diketahui f(x) = 3 - 2x² dan g(x) = 12
1.) (f + g)(7)
=> (f + g)(x) = (3 - 2x²) + 12 = 15 - 2x²
=> (f + g)(7) = 15 - 2(7)² = 15 - 2(49) = 15 - 98 = -83
2.) (fxg)(24)
=> (fxg)(x) = (3 - 2x²)(12) = 36 - 24x²
=> (fxg)(x) = 36 - 24(24)² = 36 - 13824 = -13860
3.) (f°g)(14)
=> (f°g)(x) = f[g(x)] = f(12) -> 3 - 2(144) = 3 - 288 = -285
Karena g(x) tidak mempunyai unsur x lain, maka (f°g)(14) = -285

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