tentukan jumlah mol belerang dakam 24gr pirit Fe52(ArFe=56 dan 5=36)

Mr FeS2 = 56 + 36 * 2 = 128
g = 24 gr
mol = g/mr
mol = 24/128 = 0,1875 mol

mr FeS2= 56+2(36)= 56+72= 128
molFeS2= massa/mr
             = 24/128=0,1875
mol S2= 72/128×0,1875= 0,106 mol