tolongg makasi ²log x + ²log (2x-1) = 1

LogAritMa

2'log x + 2'log (2x - 1) = 1
2'log x(2x - 1) = 2'log 2
x(2x - 1) = 2
2x² - x - 2 = 0

dg rumus abc
x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (1 ± √17)/4

Nilai x yg memenuhi :
x = (1 + √17)/4