Matematika

Pertanyaan

sec²(2x+3)+cosec²(5x-7)dx

1 Jawaban


  • f(x) = sec x → f '(x) = sec x . tan x
    f(x) = csc x → f '(x) = −csc x . cot x

    Sec²(2x+3)dx
    = 2Sec (2x+3)xSec(2x+3)tan(2x+3) ×2
    =4×Sec (2x+3)xSec(2x+3)tan(2x+3)

    cosec²(5x-7)dx
    =2cosec(5x-7)x(-cosec)(5x-7)cotan(5x-7) ×5
    =-10cosec(5x-7)x(cosec)(5x-7) cotan(5x-7)


    Sec²(2x+3)+cosec²(5x-7)dx

    = 4×Sec (2x+3)xSec(2x+3)tan(2x+3) -
    10cosec(5x-7)x(cosec)(5x-7) cotan(5x-7)

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