integral x (x+3)⁴dx Tolong pakai caranya ya

∫ x (x+3)⁴ dx
Misal u=x+3 , x=u-3
du/dx = 1
du=dx

∫(u-3)u⁴ du
=>∫u⁵ - 3u⁴ du
=>u⁶/6 - 3u⁵/5 du
=>(x+3)⁶/6 - 3(x+3)⁵/5 + C