tolong dibantu ya kak

Materi : Eksponen dan Logaritma
Bahasan : Sifat - Sifat Eksponen
Jawaban : 3

Langkah - langkah :
[tex] \frac{ 3^{x+1} + 3^{x + 2} + 3^{x + 3} }{39} = 27 \\ \\ 3^{x+1} + 3^{x + 2} + 3^{x + 3} = 1053 \\ \\ Faktorkan : \\ \\ 3^{x + 1} + 3.3^{x + 1} + 3^{2}. 3^{x+1} = 1053 \\ \\ 3^{x + 1}(1 + 3 + 3^{2} ) = 1053 \\ \\ 3^{x + 1}.13 = 1053 \\ \\ 3^{x + 1} = 81 \\ \\ 3^{x + 1} = 3^4 \\ \\ x + 1 = 4 \\ \\ x = 3 \\ \\ Pembuktian : \\ \\ \frac{81 + 243 + 729}{39} = 27 \\ \\ \frac{1053}{39} = 27 \\ \\ 27 = 27 [/tex]