Matematika

Pertanyaan

sin alpha = 1/5 akar 13 alpha sudut lancip nilai cos=?

2 Jawaban

  • cos^2 x = 1- sin^2 x
    cos^2 x = 1- (13/25)
    = 12/25
    cos x = 1/5 akar 12
  • sinα=1/5(√13)
    misal segitiga siku2 ABC
    sinα=BC/AC
    BC=√13
    AC=5
    AB=√AC²-BC²=√25-13 =2√3
    cosα=AB/AC=(2√3)/5

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