persamaan nilai mutlak 1. |8-4x| = 12 2. |y+1| -6 = 3 3. |x-3| = 12 4. |3x-2| = x+4 mohon dijwb semuanya

1.|8-4x| =12
8-4x=12
-4x=12-8
-4x=4
x=4/-4
x=-1
2.|y+1|-6=3
|y+1|=3+6
|y+1|=9
y+1=9
y=9-1
y=8
3.|x-3|=12
x-3=12
x=12+3
x=15
4.|3x-2| = x+4
3x-2=x+4
3x-x=4+2
2x=6
x=6/2
x=3